Find the general values of `theta` from the following equations:
`sqrt(3)sintheta-costheta=sqrt(2)`

Explanation

To solve the equation \( \sqrt{3} \sin \theta - \cos \theta = \sqrt{2} \), we will follow these steps:

### Step 1: Rearranging the Equation
We start with the equation:
\[ \sqrt{3} \sin \theta - \cos \theta = \sqrt{2} \]
We can rearrange this to isolate the trigonometric functions:
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