solve the following equations`3costheta-sqrt(7)sintheta=2`, When `sin48^(2)35^(')=3/4`.

Explanation

To solve the equation \(3 \cos \theta - \sqrt{7} \sin \theta = 2\) given that \(\sin(48^\circ 35') = \frac{3}{4}\), we will follow these steps:

### Step 1: Rewrite the equation in a standard form
We start with the equation:
\[ 3 \cos \theta - \sqrt{7} \sin \theta = 2 \]
This can be compared to the form \(A \cos \theta + B \sin \theta = C\).
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