Find the general values of `theta` from the following equations:
`sqrt(2)sectheta+tantheta=1`

Explanation

To solve the equation \( \sqrt{2} \sec \theta + \tan \theta = 1 \) for the general values of \( \theta \), we can follow these steps:

### Step 1: Rewrite the trigonometric functions
We start with the equation:
\[ \sqrt{2} \sec \theta + \tan \theta = 1 \]
We know that:
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