find general value of `theta` : `sintheta=-1/2` and `costheta=-sqrt(3)/2`

Explanation

To find the general value of \( \theta \) for the equations \( \sin \theta = -\frac{1}{2} \) and \( \cos \theta = -\frac{\sqrt{3}}{2} \), we will solve each equation step by step.

### Step 1: Solve \( \sin \theta = -\frac{1}{2} \)

We know that \( \sin \theta = -\frac{1}{2} \) corresponds to angles where the sine function is negative. The reference angle for \( \sin \theta = \frac{1}{2} \) is \( \frac{\pi}{6} \).

Since sine is negative in the third and fourth quadrants, we can find the angles:

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