Find the general values of `theta` from the following equations:
`cottheta=-sqrt(3)` and `"cosec"theta=2`

Explanation

To find the general values of \( \theta \) from the equations \( \cot \theta = -\sqrt{3} \) and \( \csc \theta = 2 \), we will solve each equation step by step.

### Step 1: Solve \( \cot \theta = -\sqrt{3} \)

1. We know that \( \cot \theta = \frac{1}{\tan \theta} \). Therefore, \( \cot \theta = -\sqrt{3} \) implies that \( \tan \theta = -\frac{1}{\sqrt{3}} \).
2. The angle \( \theta \) for which \( \tan \theta = \frac{1}{\sqrt{3}} \) is \( \theta = \frac{\pi}{6} \).
3. Since \( \tan \theta \) is negative, \( \theta \) must be in the second or fourth quadrant.
- In the second quadrant:
...