`sintheta=sqrt(3)/2` and `tantheta=-sqrt(3)`.Then find its general solution

Explanation

To solve the problem where \( \sin \theta = \frac{\sqrt{3}}{2} \) and \( \tan \theta = -\sqrt{3} \), we will find the general solution step by step.

### Step 1: Solve for \( \sin \theta = \frac{\sqrt{3}}{2} \)

We know that:
\[ \sin \theta = \frac{\sqrt{3}}{2} \]
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