`sintheta=-1/2` and `tantheta=-1/sqrt(3)`.Then find its general solution

Explanation

To solve the problem where \( \sin \theta = -\frac{1}{2} \) and \( \tan \theta = -\frac{1}{\sqrt{3}} \), we will find the general solution step by step.

### Step 1: Analyze \( \sin \theta = -\frac{1}{2} \)

We know that \( \sin \frac{\pi}{6} = \frac{1}{2} \). Therefore, we can express our equation as:
\[ \sin \theta = -\sin \frac{\pi}{6} \]
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