In `DeltaABC`, a=3, b=4 and c=5, evaluate sin2C.

Explanation

To evaluate \( \sin 2C \) in triangle \( \Delta ABC \) where \( a = 3 \), \( b = 4 \), and \( c = 5 \), we can follow these steps:

### Step 1: Use the Cosine Law to find \( \cos C \)
The cosine law states:
\[ \cos C = \frac{a^2 + b^2 - c^2}{2ab} \]
Substituting the given values:
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