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(tan(pi/4+x))/(tan(pi/4-x)) = ((1+tanx)/...

`(tan(pi/4+x))/(tan(pi/4-x)) = ((1+tanx)/(1-tanx))^(2)`

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To solve the equation \[ \frac{\tan\left(\frac{\pi}{4} + x\right)}{\tan\left(\frac{\pi}{4} - x\right)} = \left(\frac{1 + \tan x}{1 - \tan x}\right)^2, \] we can start by applying the tangent addition and subtraction formulas. ...
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