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(cos(pi-x)cos(-x))/(sin(pi-x)cos(pi/2+x)...

`(cos(pi-x)cos(-x))/(sin(pi-x)cos(pi/2+x))=cot^(2)x`

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To solve the equation \(\frac{\cos(\pi - x) \cos(-x)}{\sin(\pi - x) \cos\left(\frac{\pi}{2} + x\right)} = \cot^2 x\), we will use trigonometric identities to simplify the left-hand side step by step. ### Step 1: Use Trigonometric Identities We will apply the following trigonometric identities: 1. \(\cos(\pi - x) = -\cos x\) 2. \(\cos(-x) = \cos x\) 3. \(\sin(\pi - x) = \sin x\) 4. \(\cos\left(\frac{\pi}{2} + x\right) = -\sin x\) ...
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