Home
Class 10
MATHS
In figure A, B and C are points on OP...

In figure A, B and C are points on OP, OQ and OR respectively such that AB || PQ and AC || PR. Show that BC || QR.

Text Solution

Verified by Experts

In figure AB||PQ (given )
` Rightarrow " " ( OA)/(AP) = (OB)/(BQ)`
( basic proportonality theorem) ….(1)
Also in figure AC||PR (given)
` Rightarrow " " (OA)/(AP) = (OC)/(CR)` ( basic proportionality theorem) …. (2)
from equatlons ( 1) and (2) , we get
`(OB)/(BQ) = (OC)/(CR)`
BC||QR ( converse of basic proportionality theorem)
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 6a|24 Videos
  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Eercise 6b|1 Videos
  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Questions|1 Videos
  • STATISTICS

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Answer Questions|4 Videos
  • VOLUME AND SURFACE AREA OF SOLIDS

    NAGEEN PRAKASHAN ENGLISH|Exercise Revisions Exercise Long Answer Questions|5 Videos

Similar Questions

Explore conceptually related problems

In the given figure A, B and C are points on OP, OQ and OR respectively such that AB||PQ and BC||QR. Show that AC||PR.

ABCD is a square. P, Q and Rare the points on AB, BC and CD respectively, such that AP = BQ = CR. Prove that: PQ = QR

In figure DE || OQ and DF || OR. Show that EF||QR.

In Figure, A B C is a triangle in which A B=A Cdot Point D and E are points on the sides AB and AC respectively such that A D=A Edot Show that the points B , C , E and D are concyclic.

squarePQRS is a reactangle. If A, B and C are the mid-points of PQ, PS and QR respectively, then prove that AB+AC=1/2(PR+SQ).

In three line segments OA ,OB and OC , point L ,M ,N respectively are so chosen that LM || AB and MN || BC but neither of L ,M ,N nor of A , B , C are collinear. Show that LN || AC .

In the figure, given below X and Y are the mid-points of AB and AC respectively. Given that BC = 6 cm, AB = 5-4 cm and AC = 5-0 cm, calculate the perimeter of trapezium YXBC.

Let A B C be a triangle and D and E be two points on side A B such that A D=B E . If DP || BC and EQ || AC , Then prove that PQ || AB .

In Delta ABC, AB = AC. D , E and F are mid-points of the sides BC, CA and AB respectively . Show that : AD and FE bisect each other.

In triangle ABC, angle B is obtuse. D and E are mid-points of sides AB and BC respectively and F is a point on side AC such that EF is parallel to AB. Show that BEFD is a parallelogram.