Home
Class 10
MATHS
In an equilateral triangle ABC , D is t...

In an equilateral triangle ABC , D is the mid-point of AB and E is the mid-point of AC. Find the ratio between ar (` triangleABC ) : ar(triangleADE)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio between the area of triangle ABC and the area of triangle ADE, we can follow these steps: ### Step 1: Understanding the Triangle Given an equilateral triangle ABC, we know that all sides are equal and all angles are 60 degrees. D is the midpoint of side AB, and E is the midpoint of side AC. ### Step 2: Applying the Midpoint Theorem By the midpoint theorem, the line segment DE (connecting the midpoints D and E) is parallel to the side BC of triangle ABC. This means that triangles ADE and ABC are similar. ### Step 3: Establishing Similarity Since DE is parallel to BC, we can say that: - Angle DAE = Angle BAC (common angle) - Angle ADE = Angle ABC (corresponding angles) - Angle AD = Angle ACB (corresponding angles) Thus, by the Angle-Angle-Angle (AAA) criterion for similarity, triangle ABC is similar to triangle ADE. ### Step 4: Ratio of Corresponding Sides Since the triangles are similar, the ratio of their areas is equal to the square of the ratio of their corresponding sides. Let’s denote: - The length of side AB = c (since ABC is equilateral, all sides are equal) - The length of side AD = c/2 (since D is the midpoint of AB) ### Step 5: Finding the Ratio of Areas The ratio of the sides is: \[ \frac{AD}{AB} = \frac{\frac{c}{2}}{c} = \frac{1}{2} \] Now, the ratio of the areas of the triangles is given by the square of the ratio of their corresponding sides: \[ \frac{ar(\triangle ADE)}{ar(\triangle ABC)} = \left(\frac{AD}{AB}\right)^2 = \left(\frac{1}{2}\right)^2 = \frac{1}{4} \] ### Step 6: Finding the Final Ratio To find the ratio of the area of triangle ABC to the area of triangle ADE, we take the reciprocal: \[ \frac{ar(\triangle ABC)}{ar(\triangle ADE)} = \frac{1}{\frac{1}{4}} = 4 \] Thus, the ratio of the area of triangle ABC to the area of triangle ADE is: \[ \text{Ratio} = 4 : 1 \] ### Final Answer The ratio between the area of triangle ABC and the area of triangle ADE is \( 4 : 1 \). ---
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Questions|4 Videos
  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Questions|1 Videos
  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Very Short Questions|9 Videos
  • STATISTICS

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Answer Questions|4 Videos
  • VOLUME AND SURFACE AREA OF SOLIDS

    NAGEEN PRAKASHAN ENGLISH|Exercise Revisions Exercise Long Answer Questions|5 Videos

Similar Questions

Explore conceptually related problems

A B C is a triangle in which D is the mid-point of BC and E is the mid-point of A D . Prove that area of triangle B E D=1/4area \ of triangle A B C . GIVEN : A triangle A B C ,D is the mid-point of B C and E is the mid-point of the median A D . TO PROVE : a r( triangle B E D)=1/4a r(triangle A B C)dot

D is the mid-point of side B C of triangle A B C and E is the mid-point of B D . If O is the mid-point of A E , prove that a r(triangle B O E)=1/8a r(triangle A B C) .

ABCD is a square, X is the mid-point of AB and Y the mid-point of BC. Prove that the triangles ADX and BAY are congruent.

In figure, A B C\ a n d\ B D E are two equilateral triangles such that D is the mid-point of B C . If A E intersects B C in F . Prove that: ar(triangle BFE)=2ar(triangle FED) .

In the given figure, D is the mid-point of BC, E is the mid-point of BD and O is the mid-point of AE. Find the ratio of area of Delta BOE and DeltaABC

A B C is a triangle in which D is the mid-point of B C and E is the mid-point of A D . Prove that area of B E D = 1/4 area of ABC.

A B C is a triangle in which D is the mid-point of B C and E is the mid-point of A Ddot Prove that area of B E D=1/4a r e aof A B Cdot

A (5, 3), B (-1, 1) and C (7, -3) are the vertices of triangle ABC. If L is the mid-point of AB and M is the mid-point of AC, show that : LM = (1)/(2) BC .

If B is the mid point of AC and C is the mid point of BD, where A,B,C,D lie on a straight line, say why AB=CD ?

D is the mid-point of side AB of the triangle ABC.E is the mid-point of CD and F is the mid-point of AE. Prove that 8 xx " area of " (DeltaAFD) = " area of " Delta ABC