If tangents are drawn from the origin to the curve y=sin x , then their points of contact lie on the curve

Tangents are drawn from the origin to the curve y = sin x . Prove that their points of contact lie on the curve x^(2) y^(2) = (x^(2) - y^(2))

Tangents are drawn from origin to the curve y = sin+cos x ·Then their points of contact lie on the curve

Tangents are drawn from the origin to the curve y=cos X . Their points of contact lie on

Tangents are drawn from the origin to curve y=sinxdot Prove that points of contact lie on y^2=(x^2)/(1+x^2)

Tangents are drawn from the origin to curve y=sinxdot Prove that points of contact lie on y^2=(x^2)/(1+x^2)

The tangent drawn from the origin to the curve y=2x^2+5x+2 meets the curve at a point whose y-coordinate is negative. Find the area if the figure is bounded by the tangent between the point of contact and origin, the x-axis and the parabola.

Tangents are drawn from the point (4, 2) to the curve x^(2)+9y^(2)=9 , the tangent of angle between the tangents :

The points of contact of the tangents drawn from the origin to the curve y=sinx, lie on the curve

26. The points of contact of the tangents drawn from the origin to the curve y=sinx, lie on the curve

The x-intercept of the tangent to a curve is equal to the ordinate of the point of contact. The equation of the curve through the point (1,1) is