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(1+log x)^(2)/(x)...

`(1+log x)^(2)/(x)`

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` int ((1+ log x)^(2))/(x) dx " " underset( rArr (1)/(x) dx=dt)(" Let " 1+ log x=t)`
` = int t^(2) dt = (1)/(3) t^(3) +c` lt brgt `(1)/(3) (1+ log x)^(3)+c`
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