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If * is a binary operation in N defined ...

If * is a binary operation in N defined as a*b`=a^(3)+b^(3)` , then which of the following is true :
(i) * is associative as well as commutative.
(ii) * is commutative but not associative
(iii) * is associative but not commutative
(iv) * is neither associative not commutative.

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To determine whether the binary operation \( * \) defined as \( a * b = a^3 + b^3 \) is associative and/or commutative, we will analyze both properties step by step. ### Step 1: Check for Commutativity A binary operation \( * \) is commutative if for all \( a, b \in \mathbb{N} \), the following holds: \[ a * b = b * a \] **Calculation:** - Calculate \( a * b \): \[ a * b = a^3 + b^3 \] - Calculate \( b * a \): \[ b * a = b^3 + a^3 \] Since addition is commutative, we have: \[ a^3 + b^3 = b^3 + a^3 \] Thus, \( a * b = b * a \). **Conclusion for Commutativity:** The operation \( * \) is commutative. ### Step 2: Check for Associativity A binary operation \( * \) is associative if for all \( a, b, c \in \mathbb{N} \), the following holds: \[ (a * b) * c = a * (b * c) \] **Calculation:** - Calculate \( (a * b) * c \): \[ a * b = a^3 + b^3 \] Now, substituting this into the left side: \[ (a * b) * c = (a^3 + b^3) * c = (a^3 + b^3)^3 + c^3 \] - Calculate \( a * (b * c) \): \[ b * c = b^3 + c^3 \] Now, substituting this into the right side: \[ a * (b * c) = a * (b^3 + c^3) = a^3 + (b^3 + c^3)^3 \] **Conclusion for Associativity:** Now we need to check if: \[ (a^3 + b^3)^3 + c^3 \neq a^3 + (b^3 + c^3)^3 \] These two expressions are not equal in general for arbitrary \( a, b, c \). Thus, \( * \) is not associative. ### Final Conclusion - The operation \( * \) is commutative but not associative. ### Answer: The correct option is (ii) \( * \) is commutative but not associative. ---
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