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A block of mass 15 kg is placed on a lon...

A block of mass 15 kg is placed on a long trolley. The coeffcient os static friction between the block and the trolley is 0.18. The trolley accelerates from rest with `0.5 m s^-2` for 20 s and then moves with uniform velocity. Discuss the motion of the block as viewed by:- an observer moving with the trolley.

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A block of mass 15 kg is placed on a long trolley. The coeffcient os static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 m s^-2 for 20 s and then moves with uniform velocity. Discuss the motion of the block as viewed by:- a stationary observer on the ground.

A block of mass 15 kg is placed on a long trolley. The coefficient of friction between the block and the trolley is 0.18. The trolley accelerate from rest with 0.5 ms^-2 for 20 s and then moves with unifrom velocity. Discuss the motion of the block as viewd by an observer with the trolley.

A body from rest accelerates at rate 10 m s^(-2) for 5 seconds and then moves with constant velocity for 10 seconds .Find the total distance travelled by it.

The rear side of a truck is open and a box of 40 kg mass is placed 5 m away from the open end as shown. The coefficient of friction between the box and the surface below its is 0.15. On a straight road, the truck starts from rest and accelerates with 2 ms^-2 . At what distance from the starting point does the box fall off the truck ?/ (Ignore the size of the box).

The rear side of a truck is open and a box of 40 kg mass is placed 5 m away from the open end as shown in Fig. 5.22. The coeffcient of friction between the box and the surface below it is 0.15. On a straight road, the truck starts from rest and accelerates with 2 m s^-2 . At what distance from the starting point does the box fall off the truck? (Ignore the size of the box).

What is the acceleration of the block and trolley system shown in the figure, if the coefficient of kinetic friction between the trolley and the surface is 0.04?/ What is the tension in the string? (Take g = 10 ms^-2 ) Neglect the mass of the string.

Figure 5.18 shows a man standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s^-2 . What is the net force on the man? If the coefficient of static friction between the man’s shoes and the belt is 0.2, up to what acceleration of the belt can the man continue to be stationary relative to the belt ? (Mass of the man = 65 kg.)

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