Answer the following questions : Time period of a particle in SHM depends on the force constant k and mass m of the particle: T=`2pisqrt(m/k)`.A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum?

What is the effect on the time period of a simple pendulum, if the mass of the bob is doubled?

Check the correctness of the relation T=2pisqrt((l)/(g)) , where T is the time period, l is the length of pendulum and g is acceleration due to gravity.

The time period of a simple pendulum is 2 seconds. If its length is increased by 4 times, then its period becomes

Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get a homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life One of its examples is the use of ethylene glycol and water mixture as an anti-freezing liquid in the radiator of automobiles.A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9.Given: Freezing point depression constant of water (Kfwater​)=1.86Kkgmol−1Freezing point depression constant of ethanol(Kfethanol​)=2.0Kkgmol−1 Boiling point elevation constant of water(Kbwater​)=0.52Kkgmol−1 Boiling point elevation constant of ethanol (Kbethanol​)=1.2Kkgmol−1 Standard freezing point of water =273K Standard freezing point of ethanol =155.7K Standard boiling point of water =373K Standard boiling point of ethanol =351.5K Vapour pressure of pure water =32.8mmHg Vapour pressure of pure ethanol =40mmHg Molecular weight of water =18gmol−1 Molecular weight of ethanol =46gmol−1 In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. Water is added to the solution M such that the mole faraction of water in the solution becomes 0.9. the boiling point of this solution is

Answer the following questions : The motion of a simple pendulum is approximately simple harmonic for small angle oscillations. For larger angles of oscillation, a more involved analysis shows that T is greater than 2pisqrt(l/g) . Think of a qualitative argument to 9 appreciate this result

The acceleration due to gravity on the surface of moon is 1.7 m s^-2 . What isthe time period of a simple pendulum on the surface of moon if itstime period on the surface of earth is 3.5 s? (gon the surface of earth is 9.8 m s6-2 )