Answer the following questions : The motion of a simple pendulum is approximately simple harmonic for small angle oscillations. For larger angles of oscillation, a more involved analysis shows that T is greater than `2pisqrt(l/g)` . Think of a qualitative argument to 9 appreciate this result

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to 2% in the value of l.

Answer the following questions : Time period of a particle in SHM depends on the force constant k and mass m of the particle: T= 2pisqrt(m/k) .A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum?

The time t of a complete oscillation of a simple pendulum of length l is given by the equation T=2pisqrt(1/g) where g is constant. What is the percentage error in T when l is increased by 1%? Comment the above result.

A cylindrical piece of cork of density of base area Aand height h floats in a liquid of density rho_l . The cork is depressed slightly and then released. Show that the cork oscillates up and down simple harmonically with a period T= 2pisqrt((hrho)/(rho_1g)) where p is the density of cork. (Ignore damping due to viscosity of the liquid)