Check that the ratio `(ke^2)//G m_em_p` is dimensionless. Look up a Table Physical Constants and determine the value of this ratio. What does the ratio signify?

Check that the ratio ke^2/Gm_em_p is dimensionless. Look up a table of physical constants and determine the value of this ratio. What does the ratio signify.

The 6th term of a G.P. is 32 and its 8th term is 128, then the value of the common ratio is :

1M HCl and 2 M HCl are mixed in volume ratio 4:1. What is the final molarity of HCl solution?

Points A, B and C lie on the parabola y^2= 4ax . The tangents to the parabola at A, B and C, taken in pair, intersect at points P, Q and R. Determine the ratio of the areas of the triangles ABC and PQR.

In an intrinsic semiconductor the energy gap E_g is 1.2eV . Its hole mobility is much smaller than electron mobility and independent of temperature. What is the ratio between conductivity at 600K and that at 300K? Assume that the temperature dependence of intrinsic carrier concentration ni is given by n_i= n_0 exp((E_g)/(2k_BT)) where n_0 is constant.

"Equivalent mass" =("Molecular mass/Atomic mass" )/("n-factor") n-factor is very important in redox as well as non-redox reactions.With the help of n-factor we can predict the molar ratio of the reactant species specis taking part in reactions. The reciprocal of n-factor's ratio of the reactions is the molar ratio of the reactants. In general n-factor of acid/base is number of moles of H^(+)//OH^(-) furnished per mole of acid/base n-factor of a reactant is number of moles electrons lost or gained per mole of reactant. Example 1: (1)In acidic medium : KMnO_(4) (n=5)to Mn^(2+) (2) In neutral medium : KMnO_(4)(n=3) to Mn^(2+) (3) In basic medium : KMnO_(4)(n=1) to Mn^(6+) Example 2 : FeC_(2)O_(4)to Fe^(3+)+2CO_(2) Total number of moles e^(-) lost by 1 mole of FeC_(2)O_(4) =1+1xx2 implies 3 Consider the following reaction. H_(3)PO_(2)+NaOH to NaH_(2)PO_(2)+H_(2)O What is the equivalent mass of H_(3)PO_(2) ?(mol.Wt.is M)

"Equivalent mass" =("Molecular mass/Atomic mass" )/("n-factor") n-factor is very important in redox as well as non-redox reactions.With the help of n-factor we can predict the molar ratio of the reactant species specis taking part in reactions. The reciprocal of n-factor's ratio of the reactions is the molar ratio of the reactants. In general n-factor of acid/base is number of moles of H^(+)//OH^(-) furnished per mole of acid/base n-factor of a reactant is number of moles electrons lost or gained per mole of reactant. Example 1: (1)In acidic medium : KMnO_(4) (n=5)to Mn^(2+) (2) In neutral medium : KMnO_(4)(n=3) to Mn^(2+) (3) In basic medium : KMnO_(4)(n=1) to Mn^(6+) Example 2 : FeC_(2)O_(4)to Fe^(3+)+2CO_(2) Total number of moles e^(-) lost by 1 mole of FeC_(2)O_(4) =1+1xx2 implies 3 In the reaction, xVO+yFe_(2)O_(3) to FeO+V_(2)O_(5) what is the value of x and y respectively?

"Equivalent mass" =("Molecular mass/Atomic mass" )/("n-factor") n-factor is very important in redox as well as non-redox reactions.With the help of n-factor we can predict the molar ratio of the reactant species specis taking part in reactions. The reciprocal of n-factor's ratio of the reactions is the molar ratio of the reactants. In general n-factor of acid/base is number of moles of H^(+)//OH^(-) furnished per mole of acid/base n-factor of a reactant is number of moles electrons lost or gained per mole of reactant. Example 1: (1)In acidic medium : KMnO_(4) (n=5)to Mn^(2+) (2) In neutral medium : KMnO_(4)(n=3) to Mn^(2+) (3) In basic medium : KMnO_(4)(n=1) to Mn^(6+) Example 2 : FeC_(2)O_(4)to Fe^(3+)+2CO_(2) Total number of moles e^(-) lost by 1 mole of FeC_(2)O_(4) =1+1xx2 implies 3 For the reaction, Fe_0.95O("molar mass=M") to Fe_(2)O_(3) what is the eq. mass of fe_(0.95) O ?

The first term of a G.P. is 2 and the sum to infinity is 6. Find the common ratio.

An ideal gas with pressure P, volume V and temperature T is expanded isothermally to a volume 2V and a final pressure P_i , If the same gas is expanded adiabatically to a volume 2V and a final pressure P_alpha find the value of ratio P_alpha/P_i . The ratio of the specific heats for the gas is 1.67.