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For what value of lambda is the function...

For what value of `lambda` is the function defined by `f(x)={(lambda(x^2-2x),,,, if xle0),(4x+1,,,, if x>0):}` continuous at `x = 0`? What about continuity at `x = 1`?

Answer

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Knowledge Check

  • The value of k which makes the function defined by f(x) = {{:("sin" 1/x ,"if" x != 0),(k,"if" x = 0):} continuous at x = 0 is

    A
    1
    B
    2
    C
    `1/2`
    D
    `0`

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