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PSEB-CONTINUITY AND DIFFERENTIABILITY-Exercise
- Find dy/dx in the following: sin^2y + cosxy = k
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- Find dy/dx in the following: sin^2x + cos^2y = 1
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- Find dy/dx in the following: y=sin^-1(2x/(1+x^2)
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- y=tan^(-1)((3x - x^3)/(1-3x^2), -1/sqrt3<x<1/sqrt3 ਵਿੱਚ dy/dx ਪਤਾ ਕਰੋ।
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- y=cos^(-1)((1 - x^2)/(1+x^2), 0<x<1 ਵਿੱਚ dy/dx ਪਤਾ ਕਰੋ।
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- Find dy/dx in the following:y=sin^-1((1 - x^2)/(1+x^2), 0<x<1
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- Find dy/dx in the following: y=cos^-1((2x)/(1+x^2), -1<x<1
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- Find dy/dx in the following: y=sin^-1(2x sqrt(1-x^2)), -1/sqrt2ltxlt1/...
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- Find dy/dx in the following:y=sec^-1(1/(2x^2-1)), 0ltxlt1/sqrt2
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- Differentiate the following w.r.t. x: e^x/(sinx)
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- Differentiate the following w.r.t. x:e^(sin^-1x)
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- Differentiate the following w.r.t. x: e^x^3
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- Differentiate the following w.r.t. x: sin(tan^-1 e^-x)
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- Differentiate the following w.r.t. x: log(cos e^x)
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- Differentiate the following w.r.t. x: e^x+e^(x^2)+. . . .+e^(x^5)
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- Differentiate the following w.r.t. x: sqrt(e^sqrtx), x>0
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- Differentiate the following w.r.t. x: log(log x), x>1
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- Differentiate the following w.r.t. x: cosx/logx, x>0
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- Differentiate the following w.r.t. x: cos(logx + e^x)
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- Differentiate the function w.r.t. x : cosx cdot cos2x cdot cos3x
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