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The scalar product of the vector hati+ha...

The scalar product of the vector `hati+hatj+hatk` with a unit vector along the sum of vectors ` 2hati+4hatj-5hatk`and `lambdahati+2hatj+3hatk` is equal to one. Find the value of `lambda`.

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The scalar product of the vector hati+3hatj+3hatk with a unit vector along the sum of vectors hati-3hatj+4hatk and lambdahati-4hatj+5hatk is equal to one. Find the value of lambda .

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The scalar product of the vector veca=hati+hatj+hatk with a unit vector along the sum of vectors vecb=2hati+4hatj-5hatk and vecc=lambdahati+2hatj+3hatk is equal to one. Find the value of 'lambda' and hence find the unit vector along vecb+vecc .

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Find the unit vector parallel to the resultant vector of 2hati+4hatj-5hatk and hati+2hatj+3hatk .

Find the dot product of the vector 2hati+3hatj+1hatk and 1hati+2hatj+3hatk

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PSEB-VECTOR ALGEBRA-Exercise
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  5. If veca = vecb + vecc, then is it true that |veca| = |vecb| + |vecc|?...

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  6. Find the value of x for which x(hati + hatj + hatk) is a unit vector.

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  7. Find a vector of magnitude 5 units, and parallel to the resultant of t...

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  8. If veca = hati + hatj+hatk, vecb = 2hati-hatj+3hatk and vecc = hati-2h...

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  10. Find the position vector of a point R which divides the line joining t...

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  11. The two adjacent sides of a parallelogram are given by the vectors 2ha...

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  12. Show that the direction cosines of a vector equally inclined to the ax...

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  13. If veca=hati+4hatj+2hatk , vecb=3hati-2hatj+7hatk and vecc=2hati-hatj+...

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  14. The scalar product of the vector hati+hatj+hatk with a unit vector alo...

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  15. If veca, vecb, vecc are mutually perpendicular vectors of equal magnit...

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  16. Prove that (veca+vecb) cdot (veca+vecb) = |veca|^2 + |vecb|^2, if and ...

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  17. If theta is the angle between two vectors veca and vecb, then veca c...

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  18. Let veca and vecb be two unit vectors and theta is the angle between...

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  19. The value of : hati*(hatjxxhatk)+hatj*(hatixxhatk)+hatk*(hatixxhatj) i...

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  20. If theta is the angle between two vectors veca and vecb, then |veca*ve...

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