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Assume that the chances of a patient hav...

Assume that the chances of a patient having a heart attack is 40%. It is also assumed that a meditation and yoga course reduce the risk of heart attack by 30% and prescription of certain drug reduces its chances by 25%. At a time a patient can choose any one of the two options with equal probabilities. It is given that after going through one of the two options the patient selected at random suffers a heart attack. Find the probability that the patient followed a course of meditation and yoga?

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PSEB-PROBABILITY-Exercise
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  2. Suppose that 90% of people are right-handed. What is the probability t...

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  3. An urn contains 25 balls of which 10 balls bear a mark 'X' and the rem...

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  4. An urn contains 25 balls of which 10 balls bear a mark 'X' and the rem...

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  5. An urn contains 25 balls of which 10 balls bear a mark 'X' and the rem...

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  6. An urn contains 25 balls of which 10 balls bear a mark 'X' and the rem...

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  7. In a hurdle race, a player has to cross 10 hurdles. The probability th...

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  8. A die is thrown again and again until three sixes are obtained. Find t...

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  9. If a leap year is selected at random, what is the chance that it will ...

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  10. If there are two children in a family,find the probability that there ...

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  11. If a fair coin is tossed 10 times, find the probability of: at most s...

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  12. In a game, a man wins a rupee for a six and loses a rupee for any othe...

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  13. Assume that the chances of a patient having a heart attack is 40%. It ...

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  14. If each element of a second order determinant is either zero or one, w...

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  15. An electronic assembly consists of two subsystems, say, A and B. From ...

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  16. An electronic assembly consists of two subsystems, say, A and B. From ...

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  17. Bag I contains 3 red and 4 black balls and Bag II contains 4 red and 5...

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  18. If A and B are two events such that P(A) ne 0 and P(B/A) = 1, then

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  19. If P(A/B) > P(A), then which of the following is correct : :

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  20. If A and B are any two events such that : P(A) + P(B) – P(A and B) = P...

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