Silver forms ccp lattice and X-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver (Atomic mass=107.9u).

Silver forms cpp lattice and X-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate density of silver (Atomic mass 107.9 n).

A Metal crystallizes in fcc lattice and the edge of the unit cell is 620 pm. The radius of metal atom is

Silver metal crystallise with a face centred cubic .lattice. The length of unit cell is found to be 4.077 xx 10^(-8) cm . Calculate the atomic radius and density of silver (Atomic mass of Ag= 108 u, NA= 6.02 x 10^(23) mol^(-1) .

Chromium crystallizes in a body centred cubic lattice whose density is 7.20g/cm^3 . The length of the edge of the unit cell is 288.4 pm. Calculate the Avogadro number (atomic mass of chromium=52).

The face centered cubic cell of platinum ha an edge length of 0.392nm. Calculate the density of platinum (g//cm^(3)) : ("Atomic mass": Pt=195)

Lead (II) sulphide crystals has NaCl structure. What is its density ? The edge length of its unit cell is 500 pm. (Atomic mass of Pb = 207 = S = 32).

The compound CuCl has ZnS structure and the edge length of its unti cell is 500 pm. Calculate its density (At mass Cu = 63, Cl = 35.5, N_(0)=6.02xx10^(23)"mol"^(-1) )

Silver crystallines in fcc lattice. If edge length of the cell is 4.077xx10^-8cm and density is 10.5 g cm^-3 . Calculate the atomic mass of silver.

Silver has atomic mass 108 a.m.u. and density 10.5 g cm^(-3) If the edge length of its unit cell is 409 pm, identify the type of unit cell. Also calculate the radius of an atom of silver.

Silver crystallises in fcc lattice. If edge length of the cell is 4.04x10^(-8) cm and density is 10.5g cm^(-3) , calculate the atomic mass of silver.