The conductivity of `0.20 MKCl`solution at 298 K is `0.0248 S cm^-1`. Calculate its molar conductivity.

The conductivity of 0.35M NaCl solution at 298K is 0.025 S/cm. Calculate its molar conductivity .

Conductivity of 0.00241 M acetic acid is 7.896 x 10^(-5) S cm^(-1). Calculate its molar conductivity. If A°_m for acetic acid is 390.5 S cm^2 mol^(-1) , what is its dissociation constant?

Conductivity of 0.00241M acetic acid is 7.896xx10^-5 S cm^-1 . Calculate its molar conductivity and if Lambda^@ for acetic acid is 390.5 S cm^2 mol^-1 . What is its dissociation constant?

The conductivity of 0.001 mol L^-1 solution of CH_3COOH is 3.905xx10^-5 S cm^-1 . Calculate the molar conductivity and degree of dissociation Give that lambda^@(H^+)=349.65 S cm^2 mol^-1 and lambda^@(CH_2COO^-40.9 S cm^2 mol^-1 .

The conductivity of a solution containing 1.0 g of anhydrous BaCl_2 in 200 cm^3 of the solution has been found to be 0.0058 S cm^-1 . Calculate the molar conductivity and equivalnet conductivity of the solution.

A 0.05 M NaOH solution offered a resistance of 31.6 ohm ina conductivity cell at 298 K. if the area of the plates of the conductivity cell is 3.8 cm^2 and distance between them 1.4 cm. calculate the molar conductivity of the NaOH solution.

The molar conductivity of a solution of a weak acid HX(0.01M) is 10 times smaller than the molar conductivity of a solution of a weak acid HY(0.10M). If lambda_(X)^@ = lambda_(Y)^@ , the difference in their pK_a values, pK_a(HX)-pK_a(HY)

The conductivity of 0.001028 mol L^(-1) acetic acid is 4.95 xx 10^-5 S cm^-1 . Calculate its dissociation constant if A_m^@ for acetic acid is 390.5 S cm^2 mol^(-1).

The resistance of a conductivity cell containing 0.001M KC1 solution at 298 K is 1500 . What is the cell constant if conductivity of 0.001M KC1 solution at 298 K is 0.146 x 10“3 S cm-1.

The conductivity of 0.1 n NaOH solution is 0.022 S cm^(-1) .When equal volume of 0.1 N HCl solution is added, the conductivity of resultant solution is decreased to 0.0055 S cm^(-1) . The equivalent conductivity of NaCl solution is :