Calculate the equivalent conductivity of 1M H2SO4 solution whose conductivity is 26 (10 ) s /cm

The resistance of 0.5N solution of an electrolyte ina conductivity cell was found to be 25Omega . Calculate the equivalent conductivity of the solution if the electrodes in the cell are 1.6cm apart & having an area of cross section 3.2cm^(2)

Calculate the limiting molar conductivity of CaSO_4 limiting molar conductivities of calcium and sulphate ions are 119.0 and 106.0 Scm^2 mol^-1 respectively.

The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the molar conductivity of 0.02 M NaCl solution in S m^2 mol^-1 . Given: Conductivity of 0.1 M KCl solution at 298K = 1.29 S m^-1 .

The resistance of a 0.5 M solution of an electrolyte in a conductivity 'cell was found to be 25 ohm. Calculate the molar conductivity of the solution, if the electrodes in the cell are 1.6 cm apart and have an area of 3*2cm^(2) .

The resistance of a 0.5M solution of an electrolyte was found to be 30Omega . Calculate the molar conductivity of the solution if the electrods in the cell are 1.5 cm a part and having an area of cross section is 2.0 cm^(2) .

The resistance of a 0.25 mol or solution of an molar solution of an electrolyte was found to be 75Omega . Calculate the molar conductivity of the solution if the electrods in the cell are 1.8 cm a part and having an area of cross section 3.6cm^(2) .

Resistance of a conductivity cell filled with 0.1 mol L^-1 KC1 solution is 100Omega .If the resistance of the same cell when filled with 0.02 mol L^(-1) KC1 solution is 520Omega , calculate the conductivity and molar conductivity of 0.02 mol L^(-1) KC1 solution. The conductivity of 0.1 mol L(-1) KCI solution is 1.29 S/m.

Equivalent conductivity of Fe_(2)(SO_(4))_(3) is relative to molar conductivity by the expression :

When a certain conductance cell was filled 0.1 mol L^-1 KCl, it has a resitance of 85 ohm and 25^@C . When the same cell was filled with an aqueous solution of 0.052 mol L^-1 of an electrolyte solution, the resistance was 96ohm . Calculate the molar conductivity of the electrolyte at this concentration. (conductivity of 0.1 mol L^-1 KCl solution is 1.29xx10^-2 S cm^-1 )