The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y ?

Reaction AtoB follows second order kinetics. Doubling the concentration of A wil increase the rate of formation of B by a factor of :

For the reaction : 2A rarr A_2 , the rate of reaction becomes 27 times When the Concentration of A is increased three times. What is the order of the reaction ?

For the reaction A + 2B rarr C , the reaction rate is doubled if the concentration of A is doubled. The rate is increased by four times when concentrations of both A and B are increased by four times. The order of the reaction is

A reaction is of first order in reactant A and of second order in reactant B. How is rate of reaction affected when (a) Concentration of B alone is increased to three times. (b) The concentration of A as well as B is doubled.

For a chemical reaction A rarr B ,it is observed that the rate of reaction doubles when the concentration of A is increased four times. The order of reaction in A is :

For a reaction X rarr Y , the rate of reaction increases by a factor of 1.857 when the concentration of x is increase by 1.5 times. What is the order of reaction with respect of X ?

For a chemical reaction X rarr Y , the rate. increases by a factor 2.25 when the concentration of X is increased by 1.5. What is the order of reaction ?

A reaction is first order in A and second order in B How is the rate affected on increasing the concentration of B three times ?