If |z| = 3, the area of the triangle whose sides are `z, omega z and z + omega z` (where `omega` is a complex cube root of unity) is

If the are of the triangle formed by z,omega z and z+omega z where omega is cube root of unity is 16sqrt(3) then |z|=?

Let z be a complex number lying on a circle centred at the origin having radius r . If the area of the triangle having vertices as z,zomega and z+zomega , where omega is an imaginary cube root of unity is 12sqrt(3) sq. units, then the radius of the circle r=

Area of triangle formed by the vertices z,omega z and z+omega z is (4)/(sqrt(3)),omega is complex cube roots of unity then |z| is (A)1(B)(4)/(3)(C)(3)/(4) (D) (4)/(sqrt(3))

If x=p+q,y=p omega+q omega^(2), and z=p omega^(2)+q omega where omega is a complex cube root of unity then xyz=

If the area of the triangle formed formed z,wz and z=wz where w is the cube root of unity is 16sqrt(3)sq units then |z|=

If z is a complex number satisfying |z-3|<=4 and | omega z-1-omega^(2)|=a (where omega is complex cube root of unity then

ABCD is a rhombus in the argand plane.If the affixes of the vertices are z_(1),z_(2),z_(3),z_(4) respectively and /_CBA=(pi)/(3) then find the value of z_(1)+omega z_(2)+omega^(2)z_(3) where omega is a complex cube root of the unity

If z^(2)(bar(omega))^(4)=1 where omega is a nonreal complex cube root of 1 then find z .

Let z be a complex number satisfying z^(117)=1 then minimum value of |z-omega| (where omega is cube root of unity) is