The common chord of the circles `x^(2)+y^(2)-4x-4y=0` and `2x^(2)+2y^(2)=32` subtends at the origin an angle equal to

If the common chord of the circles x^(2)+(y-2)^(2)=16 and x^(2)+y^(2)=16 subtend a angle at the origin then lambda is equal to

(A) Number of values of a for which the common chord of the circles x^(2)+y^(2)=8 and (x-a)^(2)+y^(2)=8 subtends a right angle at the origin is

The common chord of x^(2)+y^(2)-4x-4y=0 and x^(2)+y^2=4^(2) subtends and angle alpha at the origin, then alpha equals

Find the angle which the common chord of x^(2)+y^(2)-4x=0 and x^(2)+y^(2)=16 subtends at the origin.

If the common chord of the circles x^(2) + ( y -lambda)^(2) =16 and x^(2) +y^(2) =16 subtend a right angle at the origin then ' lambda' is equal to :

The length of the common chord of the circles x^(2)+y^(2)-2x-1=0 and x^(2)+y^(2)+4y-1=0 , is

If 2x-3y=0 is the equation of the common chord of the circles x^(2)+y^(2)+4x=0 and x^(2)+y^(2)+2 lambda y=0 then the value of lambda is

The equation of the circle described on the common chord of the circles x^(2)+y^(2)-4x-5=0 and x^(2)+y^(2)+8y+7=0 as a diameter,is