If `f(theta) =|[cos^(2) theta,cos theta sin theta,-sin theta],[cos theta sin theta,sin^(2) theta,cos theta],[sin theta, -costheta,0]|` then, `f(pi /6) +f(pi /3) +f(pi /2) +f((2 pi) /3) +f((5 pi) /6) +f(pi)` is equal to

If f(theta)=|[cos^(2)theta,cos theta sin theta,-sin theta],[cos theta sin theta,sin^(2)theta,cos theta],[sin theta,-cos theta,0]| , then f((pi)/(12))

If f (theta) = [[cos^(2) theta , cos theta sin theta,-sin theta],[cos theta sin theta , sin^(2) theta , cos theta ],[sin theta ,-cos theta , 0]] "then " f (pi/7) is

If f(theta)=|(cos^(2)theta ,cos theta sin theta, -sin theta),(cos theta sin theta, sin^(2)theta,cos theta),(sin theta,-cos theta,0)| then, f((pi)/(6))+f((pi)/(3))+f((pi)/(2))+f((2pi)/(3))+f((5pi)/(6))+f(pi)+……+f((53pi)/(6)) is equal to

The value of f(pi/6) where f(theta)=|{:(cos^2theta,costhetasintheta,-sintheta),(costhetasintheta,sin^2theta,costheta),(sintheta,-costheta,0):}|

Consider f(theta)=|[tan theta,cos theta,sin theta],[cos theta,sin theta,tan theta],[sin theta,tan theta,cos theta]| then f((pi)/(4))+f(0) = ?

If (cos theta+cos2 theta)+sin2 theta(1+2cos theta)=2sin theta,theta in[-pi,pi] then

If 0

Let f_(n)(theta)=(sin theta+sin2 theta+sin3 theta++sin n theta)/(cos theta+cos2 theta+cos3 theta++cos n theta)

If f(theta)=[(cos theta, -sin theta,0),(sin theta, cos theta, 0),(0,0,1)] then {f(theta)^(-1)} is equal to

If sin(pi cos theta)=cos(pi sin theta),then sin2 theta=