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If sin^(-1)x +cos^(-1)y +sin^(-1)z=2pi t...

If `sin^(-1)x +cos^(-1)y +sin^(-1)z=2pi` then `2x-z+y` is :

A

4

B

2

C

0

D

3

Text Solution

Verified by Experts

The correct Answer is:
A
`-(pi)/(2) le sin^(-1) x le (pi)/(2)`
`-(pi)/(2) le sin^(-1)z le (pi)/(2)`
`0 le cos^(-1) y le pi`
Take ` sin^(-1)x =(pi)/(2)`
`sin^(-1)z=(pi)/(2)`
`cos^(-1)y=pi`
`:.x=1, z=1, y= -1`
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