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If sin^(-1)x +sin^(-1)y =pi then cos^(-1...

If `sin^(-1)x +sin^(-1)y =pi` then `cos^(-1)x +cos^(-1)y` is :

A

`pi`

B

`(pi)/(2)`

C

0

D

`2pi`

Text Solution

Verified by Experts

The correct Answer is:
C

`sin^(-1)x =(pi)/(2) rArr x = "sin"(pi)/(2)=1`
`sin^(-1)y =(pi)/(2) rArr y = "sin"(pi)/(2) =1`
`:.cos^(-1)1+cos^(-1)1=0+0=0`
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