Statement I: Mn can show maximum oxidation state of +7
Statement II: Total number of valence shell electrons present in Mn is 5. 

Options

A. If both Statement I and Statement II are true and Statement II is the correct explanation of Statement I.
B. If both Statement I and Statement II are true but Statement II is not the correct explanation for Statement I.
C. If Statement I is true but Statement II is false.
D. If Statement I is false but Statement II is true.

Answer

To analyze the statements regarding manganese (Mn), we will break down the information step by step.

### Step 1: Determine the Atomic Number and Electron Configuration of Manganese
- Manganese has an atomic number of 25.
- Its electron configuration is \( [Ar] 4s^2 3d^5 \).

### Step 2: Identify the Valence Electrons
- The valence electrons of an element are those in the outermost shell. For manganese, the outermost shell is the 4s and 3d subshells.
- In manganese, there are 2 electrons in the 4s subshell and 5 electrons in the 3d subshell.
- Therefore, the total number of valence electrons in manganese is \( 2 + 5 = 7 \).

### Step 3: Determine the Maximum Oxidation State
- The maximum oxidation state of an element can be determined by the number of valence electrons it can lose.
- Since manganese has 7 valence electrons, it can theoretically lose all 7 electrons to achieve a +7 oxidation state.
- Thus, manganese can indeed show a maximum oxidation state of +7.

### Step 4: Evaluate the Statements
- **Statement I**: "Mn can show maximum oxidation state of +7."
- This statement is **True**.

- **Statement II**: "Total number of valence shell electrons present in Mn is 5."
- This statement is **False** since we calculated that manganese has 7 valence electrons.

### Conclusion
- Statement I is true, while Statement II is false.

### Final Answer
- Statement I is true.
- Statement II is false.

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