Match the atoms/ions with their corresponding electron affinity. (eV/atom).
`{:("Column-I","Column-II"),((P) F,(1) 3.4),((Q) F^(+),(2) 17.4),((R) Cl,(3) 13),((S) Cl^(+) ,(4)3.6):}`

Options

A. `{:(P,Q,R,S),(1,3,4,2):}`
B. `{:(P,Q,R,S),(2,1,3,4):}`
C. `{:(P,Q,R,S),(1,2,4,3):}`
D. `{:(P,Q,R,S),(3,1,2,4):}`

Answer

To solve the problem of matching the atoms/ions with their corresponding electron affinity, we will analyze each atom/ion in Column I and determine their electron affinity values from Column II.

### Step-by-Step Solution:

1. **Understanding Electron Affinity**:
- Electron affinity is the amount of energy released when an electron is added to an atom or ion. Higher values indicate a greater tendency to accept an electron.

2. **Analyzing Fluorine (F)**:
- Fluorine is a highly electronegative atom and has a small atomic size, which allows it to attract electrons effectively.
- The electron affinity of fluorine is known to be approximately **3.4 eV/atom**.
- **Match**: P (F) matches with (1) 3.4.

3. **Analyzing Fluorine Ion (F⁺)**:
- The F⁺ ion is positively charged and less stable, making it more likely to attract an electron.
- The electron affinity for F⁺ is significantly higher, approximately **17.4 eV/atom**.
- **Match**: Q (F⁺) matches with (2) 17.4.

4. **Analyzing Chlorine (Cl)**:
- Chlorine is also a halogen and has a larger atomic size than fluorine, but it still has a high electron affinity due to its electronegativity.
- The electron affinity of chlorine is approximately **3.6 eV/atom**.
- **Match**: R (Cl) matches with (4) 3.6.

5. **Analyzing Chlorine Ion (Cl⁺)**:
- Similar to F⁺, the Cl⁺ ion is positively charged and will have a higher electron affinity due to its instability.
- The electron affinity for Cl⁺ is approximately **13 eV/atom**.
- **Match**: S (Cl⁺) matches with (3) 13.

### Final Matches:
- P (F) → (1) 3.4
- Q (F⁺) → (2) 17.4
- R (Cl) → (4) 3.6
- S (Cl⁺) → (3) 13

### Summary of Matches:
- P → 1
- Q → 2
- R → 4
- S → 3

### Correct Option:
The correct option is **Option 3**.