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The successive ionization energies (IE) ...

The successive ionization energies (IE) for an element A are as follows  
`A overset(IE_1)(rarr)A^(+) overset(IE_2)(rarr)A^(2+) overset(IE_3)(rarr) A^(3+) rarr ….`
If the `IE_1 and IE_3` values are `27 kJ mol^(-1)` and `51 kJ mol^(-1)` respectively, then the value of `IE_2` is ______`kJ mol^(-1)`. 

A

21

B

33

C

59

D

63

Text Solution

AI Generated Solution

The correct Answer is:
To find the second ionization energy (IE₂) of element A, we can analyze the relationship between the first ionization energy (IE₁), the second ionization energy (IE₂), and the third ionization energy (IE₃). The values given are: - IE₁ = 27 kJ mol⁻¹ - IE₃ = 51 kJ mol⁻¹ ### Step-by-Step Solution: 1. **Understanding Ionization Energies**: - Ionization energy is the energy required to remove an electron from an atom or ion. - The first ionization energy (IE₁) is the energy needed to remove the first electron from a neutral atom (A to A⁺). - The second ionization energy (IE₂) is the energy needed to remove the second electron from the positively charged ion (A⁺ to A²⁺). - The third ionization energy (IE₃) is the energy needed to remove the third electron from the doubly charged ion (A²⁺ to A³⁺). 2. **Analyzing the Trend**: - Generally, the ionization energy increases with each successive removal of an electron because the remaining electrons experience a greater effective nuclear charge. - This means that IE₂ should be greater than IE₁ and less than IE₃. 3. **Setting Up the Inequalities**: - From the given values, we can establish the following: - IE₁ < IE₂ < IE₃ - 27 kJ mol⁻¹ < IE₂ < 51 kJ mol⁻¹ 4. **Estimating IE₂**: - Since IE₂ must be between 27 kJ mol⁻¹ and 51 kJ mol⁻¹, we can make an educated guess. - A reasonable value that fits this range could be around the midpoint or slightly skewed towards the lower end, considering the trend of increasing ionization energies. 5. **Choosing a Value**: - A common approach is to select a value that is not too close to either extreme. - A value of 33 kJ mol⁻¹ fits well within the range and respects the trend of increasing ionization energy. 6. **Final Answer**: - Therefore, the value of IE₂ is **33 kJ mol⁻¹**.
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