If electronegativity of elements P, Q, R and S are respectively 0.8, 1.2, 1.8 and 2.5, then choose the hydroxides which are basic in nature. 

Options

A. POH
B. QOH
C. ROH
D. SOH

Answer

To determine which hydroxides of elements P, Q, R, and S are basic in nature based on their electronegativities, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Electronegativity**: Electronegativity is a measure of an atom's ability to attract and hold onto electrons. The higher the electronegativity, the stronger the bond formed with hydroxide ions (OH⁻).

2. **Identify Given Electronegativity Values**:
- Element P: 0.8
- Element Q: 1.2
- Element R: 1.8
- Element S: 2.5

3. **Analyze the Relationship Between Electronegativity and Basicity**:
- Hydroxides that are basic in nature tend to be those formed by elements with lower electronegativity. This is because lower electronegativity means the element can more easily donate hydroxide ions (OH⁻) into solution.

4. **Determine the Element with the Lowest Electronegativity**:
- Among the given elements, P has the lowest electronegativity (0.8). This indicates that P will form a hydroxide (POH) that is more likely to donate OH⁻ ions, making it basic.

5. **Conclusion**:
- The hydroxide that is basic in nature is POH, as it is formed from the element with the lowest electronegativity.

### Final Answer:
The hydroxide that is basic in nature is **POH**.

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