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Statement I: H^(-) is a stronger reducin...

Statement I: `H^(-)` is a stronger reducing agent as compared to H atom.
Statement II: The electronic configuration of `H and H^(-)` is `1s^(1)` and `1s^(2)` respectively.

A

If both Statement I and Statement II are true and Statement II is the correct explanation of Statement I.

B

If both Statement I and Statement II are true but Statement II is not the correct explanation for Statement I.

C

If Statement I is true but Statement II is false.

D

If Statement I is false but Statement II is true.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement step by step. ### Step 1: Understanding Statement I **Statement I:** `H^(-)` is a stronger reducing agent compared to the H atom. - A reducing agent is a substance that donates electrons to another substance and is oxidized in the process. - `H^(-)` (hydride ion) has an extra electron compared to the neutral hydrogen atom (H). - The hydride ion has the electronic configuration of `1s^2`, while the hydrogen atom has the configuration of `1s^1`. - The presence of an additional electron in `H^(-)` means it can easily lose this electron to become neutral hydrogen (H), thus acting as a reducing agent. ### Step 2: Understanding Statement II **Statement II:** The electronic configurations of `H` and `H^(-)` are `1s^1` and `1s^2`, respectively. - The electronic configuration of hydrogen (H) is indeed `1s^1`, indicating it has one electron in its outer shell. - The electronic configuration of the hydride ion (`H^(-)`) is `1s^2`, indicating it has two electrons in its outer shell. - Therefore, this statement is correct. ### Step 3: Analyzing the Relationship Between the Statements - While both statements are true, we need to determine if Statement II provides the correct explanation for Statement I. - Statement II describes the electronic configurations, but it does not explain why `H^(-)` is a stronger reducing agent. The reason lies in the stability of the electronic configuration and the ability to lose an electron, which is not explicitly stated in Statement II. ### Conclusion - **Statement I** is true: `H^(-)` is indeed a stronger reducing agent than H. - **Statement II** is also true: The electronic configurations are correctly stated. - However, **Statement II does not correctly explain Statement I**. Thus, the final answer is that both statements are true, but Statement II is not the correct explanation for Statement I. ### Final Answer: Both Statement I and Statement II are true, but Statement II is not the correct explanation for Statement I. ---
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