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Statement I: In alum, M^+ cannot be Li^+...

Statement I: In alum, `M^+` cannot be `Li^+`
Statement II: `Li^+` has the smallest size among alkali metal ions.

A

If both Statement I and Statement II are true and Statement II is the correct explanation of Statement I.

B

If both Statement I and Statement II are true but Statement II is not the correct explanation for Statement I

C

If Statement I is true but Statement II is false.

D

If Statement I is false and Statement II is true.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will break down each statement and provide a clear explanation for each. ### Step 1: Understanding Statement I **Statement I:** In alum, \( M^+ \) cannot be \( Li^+ \). - **Explanation:** Alum is a double sulfate compound, typically represented as \( MAl(SO_4)_2 \cdot 12H_2O \), where \( M^+ \) is a monovalent cation. Common examples of \( M^+ \) include \( Na^+ \), \( K^+ \), and \( NH_4^+ \). The reason \( Li^+ \) cannot be used as \( M^+ \) in alum is due to its small ionic size. ### Step 2: Understanding Statement II **Statement II:** \( Li^+ \) has the smallest size among alkali metal ions. - **Explanation:** Lithium (\( Li \)) is indeed the smallest alkali metal ion due to its position in the periodic table. It has fewer electron shells compared to other alkali metals, resulting in a smaller ionic radius. This small size leads to a high charge density, which influences its behavior in compounds. ### Step 3: Analyzing the Relationship Between the Statements - **Connection:** The reason \( Li^+ \) cannot be used in the formation of alum (Statement I) is that its small size does not fit well within the lattice structure that is formed with aluminum ions. The larger cations (like \( Na^+ \) or \( K^+ \)) can stabilize the lattice better due to their larger ionic sizes. ### Conclusion - Both statements are true. Statement II provides a correct explanation for Statement I. Therefore, the conclusion is that \( M^+ \) cannot be \( Li^+ \) in alum because \( Li^+ \) is too small to fit into the lattice structure formed with aluminum ions. ### Final Answer Both statements are true, and Statement II is the correct explanation for Statement I. ---
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