Natural gas `(CH_4) + ` Sulphur`underset(("catalysed by "AI_2O_3 or "silica gel")overset(600^@C) toA+H_2S`
Compound A can also be prepared by heating charcoal and sulphur vapour at about `850^@C`
Which of the following properties are correct for A?.

Options

A. It is highly inflammable.
B. It is very poisonous, affecting brain and central nervous system.
C. It is a colourless volatile liquid having very low flash point (`30^@C`)
D. All of these

Answer

To solve the question, we need to identify the compound A formed from the reaction of natural gas (methane, CH₄) with sulfur (S) under specific conditions. Let's break down the steps:

### Step 1: Identify the Reaction
The reaction given is:
\[ \text{CH}_4 + \text{S} \xrightarrow{\text{Al}_2\text{O}_3 \text{ or silica gel}, 600^\circ C} A + \text{H}_2\text{S} \]

### Step 2: Determine Compound A
From the video transcript, it is stated that compound A is carbon disulfide (CS₂). This can also be confirmed by the alternative method mentioned, where charcoal (carbon) reacts with sulfur vapor at a higher temperature (850°C) to produce carbon disulfide.

### Step 3: Write the Reaction for Confirmation
The formation of carbon disulfide can be represented as:
\[ \text{C} + 2\text{S} \rightarrow \text{CS}_2 \]

### Step 4: Properties of Carbon Disulfide (CS₂)
Now, we need to discuss the properties of carbon disulfide (A):
1. **Physical State**: CS₂ is a colorless, volatile liquid.
2. **Solubility**: It is soluble in organic solvents but insoluble in water.
3. **Odor**: It has a sweet odor, which can be quite strong and is often described as similar to that of ether.
4. **Flammability**: CS₂ is highly flammable and can form explosive mixtures with air.
5. **Chemical Reactivity**: It can react with various substances, including metals and halogens.

### Conclusion
Thus, compound A is carbon disulfide (CS₂), and we have identified its properties.

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