The answer to each of the following questions is a non- negative integer.
The difference in oxidation states of two nitrogen atoms of cationic part and anionic part `N_2O_5` is……………….

Answer

To solve the question regarding the difference in oxidation states of two nitrogen atoms in the cationic part and anionic part of \( N_2O_5H \), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Components of \( N_2O_5H \)**:
- The compound \( N_2O_5H \) consists of nitrogen (N), oxygen (O), and hydrogen (H).
- The cationic part is typically associated with the positive charge, while the anionic part is associated with the negative charge.

2. **Determine the Oxidation State of Nitrogen in the Cationic Part**:
- The cationic part of \( N_2O_5H \) can be considered as \( N_2O_5^+ \).
- Let the oxidation state of nitrogen in this part be \( X \).
- The oxidation state of oxygen is \(-2\). Since there are 5 oxygen atoms, the total contribution from oxygen is \( 5 \times (-2) = -10 \).
- The overall charge of the cationic part is +1.
- Therefore, we can set up the equation:
\[ 2X - 10 = +1 \]
- Solving for \( X \):
\[ 2X = 1 + 10 \implies 2X = 11 \implies X = \frac{11}{2} = 5.5 \]
- However, this indicates a mistake in the assumption of the charge. The correct cationic part should be \( N_2O_5^{2+} \) or similar. Let's assume \( N_2O_5 \) is neutral and consider the oxidation state of nitrogen in \( N_2O_5 \) directly.

3. **Determine the Oxidation State of Nitrogen in the Anionic Part**:
- For the anionic part, we can consider \( N_3N \) (which is a hypothetical anion).
- Let the oxidation state of nitrogen in this part also be \( Y \).
- The total contribution from the 3 nitrogen atoms must balance the charge.
- Assuming \( N_3N \) has a charge of -1, we can set up the equation:
\[ 3Y - 6 = -1 \]
- Solving for \( Y \):
\[ 3Y = -1 + 6 \implies 3Y = 5 \implies Y = \frac{5}{3} \approx 1.67 \]
- This also indicates a mistake in the assumption. Let's consider the oxidation state of nitrogen in \( N_2O_5 \) directly.

4. **Calculate the Difference in Oxidation States**:
- After correcting the assumptions, we find that both nitrogen atoms in the cationic and anionic parts have an oxidation state of +5.
- Therefore, the difference in oxidation states is:
\[ |5 - 5| = 0 \]

### Final Answer:
The difference in oxidation states of the two nitrogen atoms of the cationic part and anionic part of \( N_2O_5H \) is **0**.