The state of hybridization in anionic part of solid `Cl_2O_6` is

Options

A. `sp^3d^2`
B. `sp^3d`
C. `sp^3`
D. `sp^2`

Answer

To determine the state of hybridization in the anionic part of solid \( Cl_2O_6 \), we can follow these steps:

### Step 1: Identify the Anionic Part
The compound \( Cl_2O_6 \) consists of a cationic part and an anionic part. The cationic part is \( ClO_2^+ \) and the anionic part is \( ClO_4^- \).

**Hint:** Break down the compound into its cationic and anionic components to analyze their hybridization separately.

### Step 2: Determine the Central Atom and Its Valence Electrons
In the anionic part \( ClO_4^- \), the central atom is chlorine (Cl). Chlorine has 7 valence electrons.

**Hint:** Remember that the number of valence electrons for an element can be found from its group number in the periodic table.

### Step 3: Adjust for the Charge of the Anion
Since \( ClO_4^- \) has a negative charge, we add one extra electron to the total count of valence electrons. Therefore, the total number of valence electrons for the central chlorine atom in \( ClO_4^- \) is:
\[ 7 \text{ (from Cl)} + 1 \text{ (due to -1 charge)} = 8 \]

**Hint:** Always adjust the valence electron count based on the charge of the ion.

### Step 4: Calculate the Hybridization Index
The hybridization index can be calculated using the formula:
\[ \text{Hybridization Index} = \frac{\text{Total Valence Electrons}}{2} \]
For the anionic part \( ClO_4^- \):
\[ \text{Hybridization Index} = \frac{8}{2} = 4 \]

**Hint:** The hybridization index gives insight into the type of hybridization present.

### Step 5: Determine the Type of Hybridization
A hybridization index of 4 corresponds to \( sp^3 \) hybridization.

**Hint:** Familiarize yourself with the hybridization types and their corresponding indices:
- 2 = \( sp \)
- 3 = \( sp^2 \)
- 4 = \( sp^3 \)
- 5 = \( sp^3d \)
- 6 = \( sp^3d^2 \)

### Conclusion
The state of hybridization in the anionic part of solid \( Cl_2O_6 \) is \( sp^3 \).

**Final Answer:** The hybridization of the anionic part \( ClO_4^- \) in \( Cl_2O_6 \) is \( sp^3 \).