Find the number of identical angles in `Cl_2O_7`

Answer

To find the number of identical angles in \( \text{Cl}_2\text{O}_7 \), we can follow these steps:

### Step 1: Determine the Structure of \( \text{Cl}_2\text{O}_7 \)

1. **Identify the molecular formula**: \( \text{Cl}_2\text{O}_7 \) consists of 2 chlorine (Cl) atoms and 7 oxygen (O) atoms.
2. **Draw the Lewis structure**: The structure of \( \text{Cl}_2\text{O}_7 \) can be represented as a central chlorine atom bonded to several oxygen atoms. The common representation includes multiple double bonds between chlorine and oxygen.

### Step 2: Analyze the Bonding

1. **Count the bonds**: In \( \text{Cl}_2\text{O}_7 \), there are multiple double bonds between chlorine and oxygen. Specifically, there are 6 equivalent \( \text{Cl} = \text{O} \) double bonds.
2. **Identify the geometry**: The presence of these double bonds and the arrangement of the atoms will influence the angles between the bonds.

### Step 3: Determine the Identical Angles

1. **Identify the angles**: In the structure of \( \text{Cl}_2\text{O}_7 \), due to the symmetrical arrangement of the oxygen atoms around the chlorine atoms, there will be several angles that are identical.
2. **Count the identical angles**: Since there are 6 \( \text{Cl} = \text{O} \) bonds, the angles formed between these bonds will be identical.

### Conclusion

The number of identical angles in \( \text{Cl}_2\text{O}_7 \) is **6**.

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