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The amount of water produced (in g) in t...

The amount of water produced (in g) in the oxidation of 1 mol of rhombic sulphur by conc. `HNO_3` to a compound with the highest oxidation state of sulphur is………….. (Given data: Molar mass of water = 18 g mol`""^(-1))`

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Verified by Experts

The correct Answer is:
288
The reaction involved is `S_(8) +48HNO_(3) to 8H_(2)SO_(4)+16H_(2)O+48NO_(2)`
Therefore the amount of `H_(2)O` produced (in g)= no. of moles `xx 18=16 xx 18=288`
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