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If Z("eff") of Mg is 2.85, then what wil...

If `Z_("eff")` of Mg is 2.85, then what will be the value of y for magnesium, where `y = ((sigma + 0.85))/(2)` ?

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To solve the problem, we need to find the value of \( y \) for magnesium given that the effective nuclear charge \( Z_{\text{eff}} \) is 2.85. The relationship provided is: \[ y = \frac{(\sigma + 0.85)}{2} \] where \( \sigma \) is the screening constant. ### Step 1: Identify the atomic number \( Z \) of magnesium The atomic number \( Z \) of magnesium (Mg) is 12. ### Step 2: Calculate the screening constant \( \sigma \) Using the formula for effective nuclear charge: \[ Z_{\text{eff}} = Z - \sigma \] We can rearrange this to find \( \sigma \): \[ \sigma = Z - Z_{\text{eff}} \] Substituting the known values: \[ \sigma = 12 - 2.85 \] Calculating this gives: \[ \sigma = 9.15 \] ### Step 3: Substitute \( \sigma \) into the equation for \( y \) Now that we have \( \sigma \), we can substitute it into the equation for \( y \): \[ y = \frac{(9.15 + 0.85)}{2} \] Calculating the numerator: \[ 9.15 + 0.85 = 10 \] Now, substituting this back into the equation for \( y \): \[ y = \frac{10}{2} \] ### Step 4: Calculate the final value of \( y \) Now we can calculate \( y \): \[ y = 5 \] Thus, the value of \( y \) for magnesium is: \[ \boxed{5} \]
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