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Among O, O^(+), O^(2+) and O^(2-) the sp...

Among `O, O^(+), O^(2+)` and `O^(2-)` the species having most positive and most negative value of `DeltaH_(eg)` are, respectively 

A

`O^(+) and O`

B

`O^(2+) and O^(2-)`

C

`O and O^(2-)`

D

`O^(2-) and O^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which species among \( O, O^+, O^{2+}, \) and \( O^{2-} \) has the most positive and most negative value of electron gain enthalpy (\( \Delta H_{eg} \)), we need to analyze the electron configurations and the stability of each species. ### Step-by-Step Solution: 1. **Understanding Electron Gain Enthalpy (\( \Delta H_{eg} \))**: - Electron gain enthalpy is the energy change when an electron is added to a neutral atom or ion. If energy is released during this process, \( \Delta H_{eg} \) is negative, indicating a high electron affinity. Conversely, if energy is required to add an electron, \( \Delta H_{eg} \) is positive, indicating low electron affinity. 2. **Analyzing the Electron Configurations**: - The electron configuration of neutral oxygen (O) is \( 1s^2 2s^2 2p^4 \). It needs 2 more electrons to achieve a stable octet configuration. - For \( O^+ \) (oxygen with one less electron), the configuration is \( 1s^2 2s^2 2p^3 \). It has a higher effective nuclear charge compared to neutral oxygen. - For \( O^{2+} \) (oxygen with two less electrons), the configuration is \( 1s^2 2s^2 2p^2 \). It has an even higher effective nuclear charge and thus a stronger attraction for additional electrons. - For \( O^{2-} \) (oxygen with two extra electrons), the configuration is \( 1s^2 2s^2 2p^6 \). It has a stable octet, and adding another electron would lead to electron-electron repulsion, making it energetically unfavorable. 3. **Determining the Most Positive \( \Delta H_{eg} \)**: - Among these species, \( O^{2-} \) has a stable octet. Adding another electron would require energy to overcome the repulsion between electrons, leading to a positive \( \Delta H_{eg} \). Therefore, \( O^{2-} \) has the most positive \( \Delta H_{eg} \). 4. **Determining the Most Negative \( \Delta H_{eg} \)**: - \( O^{2+} \) has a strong effective nuclear charge due to the loss of two electrons. This results in a high attraction for additional electrons, leading to a highly negative \( \Delta H_{eg} \). Thus, \( O^{2+} \) has the most negative \( \Delta H_{eg} \). 5. **Final Conclusion**: - The species with the most positive \( \Delta H_{eg} \) is \( O^{2-} \), and the species with the most negative \( \Delta H_{eg} \) is \( O^{2+} \). ### Summary: - **Most Positive \( \Delta H_{eg} \)**: \( O^{2-} \) - **Most Negative \( \Delta H_{eg} \)**: \( O^{2+} \)
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