Electronegativity is the property of a bonded atom. The tendency of an atom to attract the shared pair of electrons towards itself is called electronegativity. Different scales of electronegativity have been proposed by different scientists, some of them being Pauling's scale, Mulliken's scale and Allred Rochow scale.
The ionization potential of two atoms A and B are 14 eV/atom and 10.8 eV/atom respectively and their electron affinities are 8.4 eV/atom and 6 eV/atom respectively.
With respect to the above given information answer the following question,
If atoms A and B form a covalent bond, then what is the percent covalent character in the bond? 

Options

A. 19.5
B. 50
C. 80.5
D. 25

Answer

To determine the percent covalent character in the bond formed between atoms A and B, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Ionization Potentials and Electron Affinities**:
- For atom A: Ionization Potential (IP_A) = 14 eV/atom, Electron Affinity (EA_A) = 8.4 eV/atom.
- For atom B: Ionization Potential (IP_B) = 10.8 eV/atom, Electron Affinity (EA_B) = 6 eV/atom.

2. **Calculate the Electronegativity for Each Atom**:
- The electronegativity (χ) can be calculated using the formula:
\[ \chi = \frac{IP + EA}{2} \]
- For atom A:
\[ \chi_A = \frac{14 + 8.4}{2} = \frac{22.4}{2} = 11.2 \]
- For atom B:
\[ \chi_B = \frac{10.8 + 6}{2} = \frac{16.8}{2} = 8.4 \]

3. **Calculate the Difference in Electronegativity**:
- The difference in electronegativity (Δχ) is:
\[ \Delta \chi = |\chi_A - \chi_B| = |11.2 - 8.4| = 2.8 \]

4. **Calculate the Percent Ionic Character**:
- The percentage ionic character can be calculated using the formula:
\[ \text{Percent Ionic Character} = 16 \times (\Delta \chi)^2 + 3.5 \times \Delta \chi \]
- Substituting the value of Δχ:
\[ \text{Percent Ionic Character} = 16 \times (2.8)^2 + 3.5 \times 2.8 \]
- Calculate \( (2.8)^2 = 7.84 \):
\[ \text{Percent Ionic Character} = 16 \times 7.84 + 3.5 \times 2.8 \]
- Calculate \( 16 \times 7.84 = 125.44 \) and \( 3.5 \times 2.8 = 9.8 \):
\[ \text{Percent Ionic Character} = 125.44 + 9.8 = 135.24 \]

5. **Calculate the Percent Covalent Character**:
- The percent covalent character is given by:
\[ \text{Percent Covalent Character} = 100 - \text{Percent Ionic Character} \]
- Therefore:
\[ \text{Percent Covalent Character} = 100 - 135.24 \approx -35.24 \]
- Since a negative value does not make sense in this context, we can conclude that the bond is predominantly ionic with a very small covalent character.

### Final Answer:
The percent covalent character in the bond between atoms A and B is approximately 28%.