Statement I: `CH_3I + OH^(-) to CH_3OH + I^(-)` and `CF_3I + OH^(-) to CF_3OH + I^(-)`
Statement II: Both these reactions are nucleophilic substitution reactions. 

Options

A. If both Statement I and Statement II are true and Statement II is the correct explanation of Statement I.
B. If both Statement I and Statement II are true but Statement II is not the correct explanation for Statement I.
C. If Statement I is true but Statement II is false.
D. If Statement I is false but Statement II is true.

Answer

To solve the question, we will analyze both statements provided and determine their validity step by step.

### Step 1: Analyze Statement I
The first statement discusses two reactions:
1. \( CH_3I + OH^- \rightarrow CH_3OH + I^- \)
2. \( CF_3I + OH^- \rightarrow CF_3OH + I^- \)

Both reactions involve a nucleophile (\( OH^- \)) attacking the carbon atom bonded to iodine (I), leading to the substitution of iodine with a hydroxyl group (OH).

### Step 2: Determine the Nature of the Reactions
Both reactions are indeed nucleophilic substitution reactions. In these reactions:
- \( OH^- \) acts as a nucleophile, attacking the carbon atom.
- Iodine (I) is the leaving group.

### Step 3: Compare the Reactivity of the Two Compounds
However, we need to consider the structure of the compounds involved:
- \( CH_3I \) has a methyl group (which is electron-donating), making it easier for the nucleophile to attack.
- \( CF_3I \) has a trifluoromethyl group (which is electron-withdrawing), making the carbon less reactive towards nucleophilic attack.

### Step 4: Conclude on the Rate of Reactions
Due to the electron-withdrawing effect of the \( CF_3 \) group, the rate of reaction for \( CF_3I + OH^- \) will be slower compared to \( CH_3I + OH^- \). Therefore, the rates of the two reactions will not be the same.

### Step 5: Analyze Statement II
Statement II asserts that both reactions are nucleophilic substitution reactions. This is true, as established in the previous steps.

### Final Conclusion
- **Statement I** is **false** because the rates of the two reactions are not the same.
- **Statement II** is **true** because both reactions are indeed nucleophilic substitution reactions.

Thus, the final answer is that Statement I is false, and Statement II is true.

### Summary of the Solution
- Statement I: False (the rates of the reactions are not the same).
- Statement II: True (both reactions are nucleophilic substitution reactions).