The answer to each of the following is a non-negative intcger.
How many of the following oxides have higher bond angle then `F_2O?`
`H_2O,Cl_2OCIO_2,Br_2O`

Answer

To determine how many of the given oxides have a higher bond angle than \( F_2O \) (which has a bond angle of approximately 103 degrees), we will analyze the bond angles of the following oxides: \( H_2O \), \( Cl_2O \), and \( Br_2O \).

### Step-by-Step Solution:

1. **Identify the bond angle of \( F_2O \)**:
- The bond angle in \( F_2O \) (oxygen difluoride) is approximately 103 degrees due to the presence of two lone pairs on the oxygen atom.

2. **Determine the bond angle of \( H_2O \)**:
- The bond angle in \( H_2O \) (water) is approximately 104.5 degrees. This is higher than 103 degrees.

3. **Determine the bond angle of \( Cl_2O \)**:
- The bond angle in \( Cl_2O \) (dichlorine monoxide) is approximately 111 degrees. This is also higher than 103 degrees.

4. **Determine the bond angle of \( Br_2O \)**:
- The bond angle in \( Br_2O \) (dibromine monoxide) is approximately 110 degrees. This is again higher than 103 degrees.

5. **Count the oxides with higher bond angles**:
- All three oxides \( H_2O \), \( Cl_2O \), and \( Br_2O \) have bond angles greater than 103 degrees.

### Conclusion:
- Therefore, the total number of oxides that have a higher bond angle than \( F_2O \) is **3**.

### Final Answer:
The answer is **3**.

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