The answer to each of the following is a non-negative intcger.
Find the number of `pi` bonds in `(CN)_2`

Answer

To find the number of π (pi) bonds in the molecule (CN)₂, we will follow these steps:

### Step 1: Understand the structure of (CN)₂
- The molecule (CN)₂ consists of two cyanide (CN) groups. Each CN group consists of one carbon atom (C) and one nitrogen atom (N).

### Step 2: Determine the bonding in a single CN group
- In the CN group, carbon and nitrogen are connected by a triple bond. A triple bond consists of one σ (sigma) bond and two π (pi) bonds.

### Step 3: Analyze the entire (CN)₂ molecule
- Since (CN)₂ has two CN groups, we need to consider the bonding in both groups.
- Each CN group contributes two π bonds due to the triple bond.

### Step 4: Calculate the total number of π bonds
- For one CN group: 2 π bonds
- For two CN groups: 2 π bonds/group × 2 groups = 4 π bonds

### Conclusion
- Therefore, the total number of π bonds in (CN)₂ is 4.

### Final Answer
The number of π bonds in (CN)₂ is **4**.

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