Consider the following reaction (unbalanced)
`Zn+" Hot conc. " H_(2)SO_(4)toG+R+X`
`Zn+"conc."NaOHtoT+Q`
`G+H_(2)S+NH_(3)(aq)toZ("precipitate")+X+Y`
Choose the correct option (s)

Options

A. Z is dirty white in color.
B. The oxidation state of Zn in T is +1.
C. R is a V-shaped molecule.
D. Bond order of Q is l in its ground state.

Answer

A, C, D

Explanation

The complete reactions are as follows:
`Zn. +"conc". H_(2)SO_(4) to underset(G)(ZnSO_(4))+underset(R )(SO_(2))+underset(X)(H_(2)O)`
Zn+conc. NaOH `to underset((G))(Na_(2) overset(+2)(Zn)O_(2))+underset((Q))(H_(2))`
The bond order of `H_(2)` iS 1 `[sigma 1s^2]` in ground state
`ZnSO_(4)+H_(2)S+NH_(4)OH to underset("Dirty white ppt. (Z)")(ZnS downarrow) +underset(Y)(NH_(4))_(2)SO_(4)+underset(X)(H_(2)O)`